Fallo en la consulta: SELECT l.id, l.iso_code, ll.idioma FROM i18n_language l INNER JOIN i18n_language_lang ll ON l.id=ll.i18n_language_id WHERE l.estado=1 AND ll.i18n_language_lang= ORDER BY l.orden ASC
array(3) { [0]=> string(5) "42000" [1]=> int(1064) [2]=> string(166) "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ORDER BY l.orden ASC' at line 1" }